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https://colab.research.google.com/drive/1HbEYpE9GBtz5pduAF36JHF1dSsg7Cu_3
https://colab.research.google.com/drive/1QNhAMt8FkQkJ0WUG4qKsOlyK1-MHGmFh
https://colab.research.google.com/drive/1h4PC-HDc7FIn4lnpq3zVZ746dr54viOf
https://colab.research.google.com/drive/1kFGKFA17M-81U3O7-zUar7wAgMLbd-jw
https://colab.research.google.com/drive/1i5lt4zXUsapi_55v2uI2pQW48XbgvU_f

As always feel free to leave comments or suggestions and thanks for watching. Last update : Aug 18 2017Q:

Integrate a specific $y$ into an integral

I’m trying to find the value of $\iint\int e^{3x+\sqrt[3]{4}y} dxdy$. I can’t just do a substitution for $y$ because the absolute value of $\sqrt[3]{4}$ is greater than 1, so you get a delta function, which is unacceptable. I know you have to perform a change of variables, but $e^{3x+\sqrt[3]{4}y}$ is not a differentiable function, so is there any other ways to do this? I need to find the value of the above integral (or find a good approximation to it).

Note that\begin{align}\iint e^{\sqrt[3]{4}y}dy&=\int\left[\int e^{3x+\sqrt[3]{4}y}dx\right]dy\\&=\int\left[\int e^{3x+\sqrt[3]{4}y}dx\right]\left[\frac{\sqrt[3]{4}}3dy\right]\end{align}

Efficacy and safety of bevacizumab in combination with conventional chemotherapy for patients with advanced non-squamous non-small-cell lung cancer.
We investigated the efficacy and safety of bevacizumab combined with chemotherapy, as well as the efficacy and safety of the addition of bevacizumab to chemoradiotherapy. We enrolled 51 patients with stage IIIB/IV non-squamous non-small-cell lung cancer (NSCLC) who were treated with chemotherapy and radiotherapy with or without bevacizumab as the first-line treatment. The median overall survival (OS) was 17.7 months and the 1- and 2-year OS rates were 81.8 and 44.2%, respectively. The median progression-free survival (PFS) was 9.2 months and the 1- and 2-year PFS rates were 34.7 and 21.3%, respectively. Patients with stage IIIB who received bevacizumab monotherapy demonstrated a significantly better OS and PFS
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